夜猫c
问题描述
我如何制作类似的东西
x = '1 2 3 45 87 65 6 8' >>> foo(x) [1,2,3,45,87,65,6,8]
我完全卡住了，如果我按索引来做，那么超过 1 位的数字将被分解.请帮忙.
I'm completely stuck, if i do it by index, then the numbers with more than 1 digit will be broken down. Help please.
推荐答案
最简单的解决方案是使用.split()创建字符串列表:
The most simple solution is to use .split()to create a list of strings:
x = x.split()
或者，您可以将列表推导式与 .split() 方法:
Alternatively, you can use a list comprehension in combination with the .split() method:
x = [int(i) for i in x.split()]
您甚至可以使用地图 map 作为第三个选项:
You could even use map map as a third option:
x = list(map(int, x.split()))
如果你想要整数，这将创建一个 int 的 list.
This will create a list of int's if you want integers.
