小木头no
问题描述
我正在寻找与 Java 的 Float.floatToBits 等效的 Python.
I am looking for the Python equivalent of Java's Float.floatToBits.
我发现了这个 Python:获取 &操纵(作为整数)浮点数的位模式，但有人知道不那么复杂的方法吗?
I found this Python: obtain & manipulate (as integers) bit patterns of floats but does anyone know of a less complicated way?
推荐答案
Alex Martelli 在该问题中给出的答案非常简单——您可以将其简化为:
The answer that Alex Martelli gives in that question is really pretty simple -- you can reduce it to:
>>> import struct
>>>
>>>
>>> def floatToBits(f):
... s = struct.pack('>f', f)
... return struct.unpack('>l', s)[0]
...
...
>>> floatToBits(173.3125)
1127043072
>>> hex(_)
'0x432d5000'
一旦你将它作为一个整数，你可以执行任何其他你需要的操作.
Once you have it as an integer, you can perform any other manipulations you need to.
您可以将操作顺序颠倒为往返:
You can reverse the order of operations to round-trip:
>>> def bitsToFloat(b):
... s = struct.pack('>l', b)
... return struct.unpack('>f', s)[0]
>>> bitsToFloat(0x432d5000)
173.3125
