疯疯癫癫的羊
问题描述
我正在尝试使我从 QMenu 中的选择成为可检查的，以便一次只能选择一个，并且默认情况下将第一项设置为检查(这实际上有效).
I am trying to make my choices from QMenu to be checkable in a way that only one might be selected at time and first item is set checked by default (this works actually).
这是我的代码片段:
paymentType = QMenu('Payment Type', self)
paymentType.addAction(QAction('Cash', paymentType, checkable=True, checked = True))
paymentType.addAction(QAction('Noncash Payment', paymentType, checkable=True))
paymentType.addAction(QAction('Cash on Delivery', paymentType, checkable=True))
paymentType.addAction(QAction('Bank Transfer', paymentType, checkable=True))
menu.addMenu(paymentType)
有什么建议吗?谢谢！
推荐答案
一个可能的选择是使用 QActionGroup 并激活 专有属性
A possible option is to use QActionGroup and activate the exclusive property
import sys
from PyQt5.QtWidgets import *
class MainWindow(QMainWindow):
def __init__(self, *args, **kwargs):
QMainWindow.__init__(self, *args, **kwargs)
menu = self.menuBar()
paymentType = QMenu('Payment Type', self)
group = QActionGroup(paymentType)
texts = ["Cash", "Noncash Payment", "Cash on Delivery", "Bank Transfer"]
for text in texts:
action = QAction(text, paymentType, checkable=True, checked=text==texts[0])
paymentType.addAction(action)
group.addAction(action)
group.setExclusive(True)
group.triggered.connect(self.onTriggered)
menu.addMenu(paymentType)
def onTriggered(self, action):
print(action.text())
if __name__ == '__main__':
app = QApplication(sys.argv)
w = MainWindow()
w.show()
sys.exit(app.exec_())
